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10x^2+91x+120=0
a = 10; b = 91; c = +120;
Δ = b2-4ac
Δ = 912-4·10·120
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-59}{2*10}=\frac{-150}{20} =-7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+59}{2*10}=\frac{-32}{20} =-1+3/5 $
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